x+x^2=0.64

Solution for x+x^2=0.64 equation:

x+x^2=0.64

We move all terms to the left:

x+x^2-(0.64)=0

We add all the numbers together, and all the variables

x^2+x-0.64=0

a = 1; b = 1; c = -0.64;
Δ = b2-4ac
Δ = 12-4·1·(-0.64)
Δ = 3.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3.56}}{2*1}=\frac{-1-\sqrt{3.56}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3.56}}{2*1}=\frac{-1+\sqrt{3.56}}{2}
$